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I don't think so?

I think the b-tree is using the start/end sequence knowledge at each to do fewer node evaluations. That is, a b-tree is "shorter" so of course it'll take fewer node evaluations to reach the leaf.

"b-tree is equivalent to balanced binary tree", and "unbalanced tree", don't make a ton of sense when ostensibly the article compares b-trees to balanced BST.



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